捕获组分为:
从正则表达式左侧开始,每出现一个左括号"("记做一个分组,分组编号从 1 开始。0 代表整个表达式。
对于时间字符串:2017-04-25,表达式如下
(\\d{4})-((\\d{2})-(\\d{2}))
有 4 个左括号,所以有 4 个分组:
编号 | 捕获组 | 匹配 |
---|---|---|
0 | (\d{4})-((\d{2})-(\d{2})) | 2017-04-25 |
1 | (\d{4}) | 2017 |
2 | ((\d{2})-(\d{2})) | 04-25 |
3 | (\d{2}) | 04 |
4 | (\d{2}) | 25 |
public static final String DATE_STRING = "2017-04-25";
public static final String P_COMM = "(\\d{4})-((\\d{2})-(\\d{2}))";
Pattern pattern = Pattern.compile(P_COMM);
Matcher matcher = pattern.matcher(DATE_STRING);
matcher.find();//必须要有这句
System.out.printf("\nmatcher.group(0) value:%s", matcher.group(0));
System.out.printf("\nmatcher.group(1) value:%s", matcher.group(1));
System.out.printf("\nmatcher.group(2) value:%s", matcher.group(2));
System.out.printf("\nmatcher.group(3) value:%s", matcher.group(3));
System.out.printf("\nmatcher.group(4) value:%s", matcher.group(4));
每个以左括号开始的捕获组,都紧跟着?,而后才是正则表达式。
对于时间字符串:2017-04-25,表达式如下:
(?<year>\\d{4})-(?<md>(?<month>\\d{2})-(?<date>\\d{2}))
有 4 个命名的捕获组,分别是:
编号 | 名称 | 捕获组 | 匹配 |
---|---|---|---|
0 | 0 | (?\d{4})-(?(?\d{2})-(?\d{2})) | 2017-04-25 |
1 | year | (?\d{4})- | 2017 |
2 | md | (?(?\d{2})-(?\d{2})) | 04-25 |
3 | month | (?\d{2}) | 04 |
4 | date | (?\d{2}) | 25 |
命名的捕获组同样也可以使用编号获取相应值。
public static final String P_NAMED = "(?<year>\\d{4})-(?<md>(?<month>\\d{2})-(?<date>\\d{2}))";
public static final String DATE_STRING = "2017-04-25";
Pattern pattern = Pattern.compile(P_NAMED);
Matcher matcher = pattern.matcher(DATE_STRING);
matcher.find();
System.out.printf("\n===========使用名称获取=============");
System.out.printf("\nmatcher.group(0) value:%s", matcher.group(0));
System.out.printf("\n matcher.group('year') value:%s", matcher.group("year"));
System.out.printf("\nmatcher.group('md') value:%s", matcher.group("md"));
System.out.printf("\nmatcher.group('month') value:%s", matcher.group("month"));
System.out.printf("\nmatcher.group('date') value:%s", matcher.group("date"));
matcher.reset();
System.out.printf("\n===========使用编号获取=============");
matcher.find();
System.out.printf("\nmatcher.group(0) value:%s", matcher.group(0));
System.out.printf("\nmatcher.group(1) value:%s", matcher.group(1));
System.out.printf("\nmatcher.group(2) value:%s", matcher.group(2));
System.out.printf("\nmatcher.group(3) value:%s", matcher.group(3));
System.out.printf("\nmatcher.group(4) value:%s", matcher.group(4));
在左括号后紧跟?:,而后再加上正则表达式,构成非捕获组(?:Expression)。
对于时间字符串:2017-04-25,表达式如下:
(?:\\d{4})-((\\d{2})-(\\d{2}))
这个正则表达式虽然有四个左括号,理论上有 4 个捕获组。但是第一组(?:\d{4}),其实是被忽略的。当使用 matcher.group(4) 时,系统会报错。
编号 | 捕获组 | 匹配 |
---|---|---|
0 | (\d{4})-((\d{2})-(\d{2})) | 2017-04-25 |
1 | ((\d{2})-(\d{2})) | 04-25 |
2 | (\d{2}) | 04 |
3 | (\d{2}) | 25 |
public static final String P_UNCAP = "(?:\\d{4})-((\\d{2})-(\\d{2}))";
public static final String DATE_STRING = "2017-04-25";
Pattern pattern = Pattern.compile(P_UNCAP);
Matcher matcher = pattern.matcher(DATE_STRING);
matcher.find();
System.out.printf("\nmatcher.group(0) value:%s", matcher.group(0));
System.out.printf("\nmatcher.group(1) value:%s", matcher.group(1));
System.out.printf("\nmatcher.group(2) value:%s", matcher.group(2));
System.out.printf("\nmatcher.group(3) value:%s", matcher.group(3));
// Exception in thread "main" java.lang.IndexOutOfBoundsException: No group 4
System.out.printf("\nmatcher.group(4) value:%s", matcher.group(4));