python 计算列表中某个元素连续出现的次数
- a = [1, 2, 3, 4, 21, 1, 1, 2, 3, 1, 1, 1]
- b = 2 # b的值为要求的数字
- t = 0
- w = 1
- for k, v in enumerate(a):
- if k > 0:
- if v == b and a[k - 1] == b:
- t += 1
- if w < t:
- w = t
- else:
- t = 1
- print(w)
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