python 使用smtplib发送邮件 带附件 抄送多人等(亲测有效)
- import os
- import smtplib
- import base64
- from email.mime.text import MIMEText
- from email.mime.multipart import MIMEMultipart
-
-
- class SendEmail(object):
- def __init__(self, username, passwd, recv, title, content,
- file=None, ssl=False,
- email_host='smtp.163.com', port=25, ssl_port=465):
- self.username = username # 用户名
- self.passwd = passwd # 授权码,邮箱第三方登录授权码
- self.recv = recv # 收件人,多个要传list ['a@qq.com','b@qq.com]
- self.title = title # 邮件标题
- self.content = content # 邮件正文
- self.file = file # 附件路径,如果不在当前目录下,要写绝对路径
- self.email_host = email_host # smtp服务器地址,163的为smtp.163.com
- self.port = port # 普通端口
- self.ssl = ssl # 是否安全链接
- self.ssl_port = ssl_port # 安全链接端口
-
- def send_email(self):
- msg = MIMEMultipart()
- # 发送内容的对象
- if self.file: # 处理附件的
- file_name = os.path.split(self.file)[-1] # 只取文件名,不取路径
- try:
- f = open(self.file, 'rb').read()
- except Exception as e:
- raise Exception('附件打不开!!!!%s' % e)
- else:
- att = MIMEText(f, "base64", "utf-8")
- att["Content-Type"] = 'application/octet-stream'
- # base64.b64encode(file_name.encode()).decode()
- new_file_name = '=?utf-8?b?' + base64.b64encode(file_name.encode()).decode() + '?='
- # 这里是处理文件名为中文名的,必须这么写
- att["Content-Disposition"] = 'attachment; filename="%s"' % (new_file_name)
- msg.attach(att)
- msg.attach(MIMEText(self.content)) # 邮件正文的内容
- msg['Subject'] = self.title # 邮件主题
- msg['From'] = self.username # 发送者账号
- msg['To'] = ','.join(self.recv) # 接收者账号列表
- if self.ssl:
- self.smtp = smtplib.SMTP_SSL(self.email_host, port=self.ssl_port)
- else:
- self.smtp = smtplib.SMTP(self.email_host, port=self.port)
- # 发送邮件服务器的对象
- self.smtp.login(self.username, self.passwd)
- try:
- self.smtp.sendmail(self.username, self.recv, msg.as_string())
- pass
- except Exception as e:
- print('出错了。。', e)
- else:
- print('发送成功!')
- self.smtp.quit()
-
-
- if __name__ == '__main__':
-
- m = SendEmail(
- username='@163.com',
- passwd='',
- recv=[''],
- title='',
- content='测试发送邮件',
- file=r'E:\a.png',
- ssl=True,
- )
- m.send_email()
有人反馈说,如果收件人为多人时,只有第一个人可以收到。
解决办法:如果配置文件中写的 aaa@b.com,ccc@d.com,那么直接将从配置文件中读取出来的进行分割self.recv.split(',')
- self.smtp.sendmail(self.username, self.recv, msg.as_string())
- 修改为下面这句话
- self.smtp.sendmail(self.username, self.recv.split(','), msg.as_string())